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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Interference of Waves
Duration: 8.28 Min
 
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Duration: 1.59 Min
 
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Duration: 8.53 Min
 
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Duration: 12.15 Min
 
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Duration: 8.22 Min
 
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Duration: 5.22 Min
 
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Duration: 4.31 Min
 
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Module - 12 Solved Example-1
Duration: 3.03 Min
 
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Module - 13 Solved Example-2
Duration: 2.32 Min
 
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Module - 14 Solved Example-3
Duration: 1.38 Min
 
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Module - 15 Solved Example-4
Duration: 3.13 Min
 
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Module - 16 Solved Example-5
Duration: 3.08 Min
 
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Module - 17 Solved Example-6
Duration: 4.40 Min
 
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  1.  
  2. Sir while using principle of superposition why don't we use vector addition here ?
    4 years ago by Ameya Marakarkandy

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  3.  
  4. Sir I didn't understand the -phi in y2. Can you pls elaborate: y2=A2sin(w(t-phi/w)) , y2=0 at t=phi/w which is the time at which wave 2 reaches the point P so is wave 2 phi/w seconds ahead or behind?
    4 years ago by Ameya Marakarkandy

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  5.  
  6. how can we add both the displacements directly. if they are in different direction so it should be vector sum right?
    5 years ago by 1M0 4

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  7.  
  8. Why have we taken displacement as A(sinwt)
    6 years ago by Madhav Sharma

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  9.  
  10. why we have taken (-)phi not (+) phi
    8 years ago by Faizan Ali Saiyed
    Ans 1 ->
    Substitute phi as w(delta t). That is, y2 = A2Sin(w(t - delta t)). Now, since wave 2 would be starting the same way wave 1 did delta t seconds before wave 2 arrives, we have t - delta t and not t delta t
    7 years ago by Kishore Sathia

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  11.  
  12. how can we write (A1+A2cosphi)=Rcostheta and A2sinphi=Rsintheta. there should be a relation between(A1+A2cosphi) and A2sinphi ?
    9 years ago by sudeep khare
    Ans 1 ->
    In both equations these are constant values A1, A2 and phi and we are expressing these constants in terms of other constants R and theta... relation among constant is also calculated further in the video...
    9 years ago by Physics Galaxy
    Ans 2 ->
    I found to easier to think of it as working backwards: Let R be defined as R = sqrt(A1^2 A2^2 2A1A2cos(phi)). Now since (A1 A2cos(phi))^2 (A2sin(phi)^2) = R^2, we can now write that (A1 A2cos(phi)) = Rcos(theta) and A2sin(phi) = Rsin(theta) where tan(theta) = A2sin(phi)/(A1 A2cos(phi)) We could also have written that (A1 A2cos(phi)) = Rsin(beta) and A2sin(phi) = Rcos(beta), but by convention, cos is used for the former and sin for the latter. Writing it this way makes the final expression easier to remember and less congested.
    7 years ago by Kishore Sathia
    Ans 3 ->
    *A1^2 plus A2^2 plus 2A1A2cos(phi)
    7 years ago by Kishore Sathia

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